###189. Rotate Array
题目: https://leetcode.com/problems/rotate-array/
难度 : Easy
首先,要知道一点,k
如果大于nums
的长度了,那么其实进行 k % len(nums)
次就行了
其次,要注意k 为0
的情况
class Solution(object):
def rotate(self, nums, k):
"""
:type nums: List[int]
:type k: int
:rtype: void Do not return anything, modify nums in-place instead.
"""
k = k % len(nums)
if k != 0:
tmp = nums[-k:]
for j in range(len(nums)-1, k-1, -1):
nums[j] = nums[j-k]
nums[:k] = tmp
还有作弊大法,贼🐂批
class Solution(object):
def rotate(self, nums, k):
"""
:type nums: List[int]
:type k: int
:rtype: void Do not return anything, modify nums in-place instead.
"""
k %= len(nums)
nums[:] = nums[-k:] + nums[:-k]