Conditionals.py

# The value of 10*4 (40) is greater than 14+23 (37), therefore this 
# comparison expression will return the Boolean value of True.


print(10*4 > 14+23) # Should print True

# The letter "t" has a Unicode value of 116 and the letter "s" has a
# Unicode value of 115. Since 116 is not less than 115, the 
# comparison of "tall" < "short" (or 116 < 115) is False. 

print("tall" < "short")  # Should print False


####################
####################
####################


# This function accepts one variable as a parameter
def translate_error_code(error_code):
 
# The if-elif-else block assesses the value of the variable
# passed to the function as a parameter. The if statement uses 
# the equality operator == to test the value of the variable.
# This test returns a Boolean (True/False) result.
    if error_code == "401 Unauthorized":
# If the comparison above returns True, then the indented 
# line(s) inside the if-statement will run. In this case, the
# action is to assign a string to the translation variable.
# The remainder of the if-elif-else block will not run.
# The Python interpreter will skip to the next line outside of 
# the if-elif-else block. In this case, the next line is the 
# return value statement.  
        translation = "Server received an unauthenticated request"
 
# If the initial if-statement returns a False result, then the
# first elif-statement will run a different test on the value
# of the variable.
    elif error_code == "404 Not Found":
# If the first elif-statement returns a True result, then the
# indented line(s) inside the first elif-statement will run. 
# After this line, the remainder of the if-elif-else block will
# not run. The Python interpreter will skip to the next line
# outside of the if-elif-else block. 
        translation = "Requested web page not found on server"
 
# If both the initial if-statement and the first elif-statement 
# return a False result, then the second elif-statement will
# run.
    elif error_code == "408 Request Timeout":
# If the second elif-statement returns a True result, then the
# indented line(s) inside the second elif-statement will run. 
# After this line, the remainder of the if-elif-else block will
# not run. The Python interpreter will skip to the next line
# outside of the if-elif-else block. 
        translation = "Server request to close unused connection"
 
# If the conditional tests above do not produce a True result
# then the else-statement will run. 
    else:
        translation = "Unknown error code"
# The if-elif-else block ends.

# The next line outside of the if-elif-else block will run
# after exiting the block. In this case, the next line returns
# the output from the if-elif-else block.
    return translation

# The print() function allows us to display the output of the
# function. To call a function in a print statement, the syntax
# is print(name_of_function(parameter))
print(translate_error_code("404 Not Found"))

# Expected output:
# Requested web page not found on server

####################
####################
####################

# Sets value of the "number" variable
number = 25

# The "number" variable will first be compared to 5. Since it is 
# False that "number" is not less than or equal to 5, the expression indented 
# under this line will be ignored. 
if number <= 5: 
   print("The number is 5 or smaller.")
 
# Next, the "number" variable will be compared to 33. Since it is 
# False that "number" is equal to 33, the expression indented under 
# this line will be ignored. 
elif number == 33:
   print("The number is 33.")
 
# Then, the "number" variable will be compared to 32 and 6. Since it 
# is True that 25 is less than 32 and greater than 6, the Python 
# interpreter will print "The number is less than 32 and/or greater
# than 6." Then, it will exit the if-elif-else statement and the remainder 
# of the if-elif-else statement will be ignored.
elif number < 32 and number >= 6:
   print("The number is less than 32 and greater than 6.")
 
else:
   print("The number is " + str(number))
 
# Expected output is: 
# The number is less than 32 and greater than 6.


####################

# Skill Group 4

# Use an if statement to calculate a return value

# Use conditional operators

# Recall the arithmetic operators // and %

####################
####################

# This function rounds a variable number up to the nearest 10x value
def round_up(number):
  x = 10
# The floor division operator will calculate the integer value of
# "number" divided by x: 35 // 10 will return the integer 3.
  whole_number = number // x
# The modulo operator will calculate the remainder value of "number"
# divided by x: 35 % 10 will return the remainder value 5.
  remainder = number % x
# If the remainder is greater than 0: 
  if remainder >= 5: 
# Return x multiplied by the (whole_number+1) to round up
    return x*(whole_number+1)
# Else, return x multiplied by the whole_number to round down
  return x*whole_number
 
# Calls the function with the parameter value of 35.
print(round_up(35)) # Should print 40


####################
####################
####################