README.md

676. Implement Magic Dictionary

Design a data structure that is initialized with a list of different words. Provided a string, you should determine if you can change exactly one character in this string to match any word in the data structure.

Implement the MagicDictionary class:

• MagicDictionary() Initializes the object.
• void buildDict(String[] dictionary) Sets the data structure with an array of distinct strings dictionary.
• bool search(String searchWord) Returns true if you can change exactly one character in searchWord to match any string in the data structure, otherwise returns false.

Example 1:

Input:
["MagicDictionary", "buildDict", "search", "search", "search", "search"]
[[], [["hello", "leetcode"]], ["hello"], ["hhllo"], ["hell"], ["leetcoded"]]
Output:
[null, null, false, true, false, false]
Explanation:
MagicDictionary magicDictionary = new MagicDictionary();
magicDictionary.buildDict(["hello", "leetcode"]);
magicDictionary.search("hello"); // return False
magicDictionary.search("hhllo"); // We can change the second 'h' to 'e' to match "hello" so we return True
magicDictionary.search("hell"); // return False
magicDictionary.search("leetcoded"); // return False

Constraints:

• 1 <= dictionary.length <= 100
• 1 <= dictionary[i].length <= 100
• dictionary[i] consists of only lower-case English letters.
• All the strings in dictionary are distinct.
• 1 <= searchWord.length <= 100
• searchWord consists of only lower-case English letters.
• buildDict will be called only once before search.
• At most 100 calls will be made to search.

Solutions (Python)

1. Solution

class MagicDictionary:

    def __init__(self):
        self.presufban = {}

    def buildDict(self, dictionary: List[str]) -> None:
        for word in dictionary:
            for i in range(len(word)):
                prefix = word[:i]
                suffix = word[i + 1:]

                if (prefix, suffix) not in self.presufban:
                    self.presufban[(prefix, suffix)] = word[i]
                else:
                    self.presufban[(prefix, suffix)] = '?'

    def search(self, searchWord: str) -> bool:
        for i in range(len(searchWord)):
            prefix = searchWord[:i]
            suffix = searchWord[i + 1:]

            if self.presufban.get((prefix, suffix), searchWord[i]) != searchWord[i]:
                return True

        return False


# Your MagicDictionary object will be instantiated and called as such:
# obj = MagicDictionary()
# obj.buildDict(dictionary)
# param_2 = obj.search(searchWord)