Consider oneway:bus for bidirectionality

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Contributing guidelines

• I understand the contributing guidelines

Documentation

• My proposal is not addressed by the documentation or examples

Existing issues

• Nothing similar appears in an existing issue

What problem does your feature proposal solve?

Consider https://www.openstreetmap.org/way/6878440
This street is only bidirectional for buses.
When searching for a path for city buses, edges along this way are not considered.

What is your proposed solution?

Expose oneway exception types to graph API, similar to network_type.

https://wiki.openstreetmap.org/wiki/Key:oneway:bus
https://wiki.openstreetmap.org/wiki/Key:oneway:psv
https://wiki.openstreetmap.org/wiki/Key:oneway:bicycle

graph = ox.graph_from_polygon(bounds, network_type="drive_service", oneway_type="bus")
should consider oneway:bus if it exists, oneway otherwise.

What alternatives have you considered?

Workaround considered: Download graph, change oneway attribute, rebuild graph

ox.settings.useful_tags_way = list(
    dict.fromkeys(ox.settings.useful_tags_way + ["oneway:bus"])
)
graph = ox.graph_from_polygon(bounds, network_type="drive_service", simplify=False)
nodes, edges = ox.graph_to_gdfs(graph, nodes=True, edges=True)
edges["oneway"] = edges["oneway"] & ~edges["oneway:bus"].eq("no")
graph = ox.graph_from_gdfs(nodes, edges)

However, it seems to me that graph_from_gdfs does not consider oneway.

Additional context

Example: https://www.openstreetmap.org/way/6878440

[stertingen]

Functional workaround:

nodes, edges = ox.graph_to_gdfs(graph, nodes=True, edges=True)
bidirectionalEdges = edges[edges["oneway:bus"].eq("no")]
bidirectionalEdges.index.rename(["v", "u", "key"], inplace=True)
bidirectionalEdges = bidirectionalEdges.reorder_levels(["u", "v", "key"])
graph = ox.graph_from_gdfs(nodes, pd.concat([edges, bidirectionalEdges]))