My plan for my 10 minutes 11/16 (And Thursday office hours)

[jenessalemon]

I have having a hard time keeping all of the variables straight,
as there are many. On my survive function(plants.R line 69), I say that if the cell
has NA, return NA, because we don't want to change anything. I then
say that if there is already a plant there, they are going to
compete! Lastly, if the cell is empty...and if the survival value is
lower than a random draw from a uniform distribution, we still do
nothing. Else, we...and that's I am stuck in the coding. I know that I need
to assign the cell to the name of the plant that now occupies it.
What I need to know:
1- is cell a cell in the char.matrix? How will R know that we
want a single cell from our char.matrix which is (plants)? Wouldn't we have
to call the whole char.matrix and then just index it? I guess I don't understand
how we are calling "cell" as an argument.
2- how can I assign the plant name to the matrix? I am assuming
that I need to use info$names at some point, but which of the two names do we
use? I'm thinking it must be something like:
cell <- info$names(?)

Separate plant.timestep question: are we going to keep time by just doing for(i in 1:100)? That is what I got from "discrete time steps." Is there a certain amount of time we need to keep?

[willpearse]

1. Answering your questions in order: Yes. Because you will give it a single cell from your matrix. Yes. --> I think, given that you've answered every question in your question, you do therefore understand what is going on...
2. I don't really understand this question, so let's talk about it in class...