get_news()['url'] returns a URL about Google Consent Mode in GNews

[sohaibrahman64]

Is there any way to bypass Google Consent Mode in GNews get_news() function? Calling get_news()['url'] function returns a URL as follows:

https://consent.google.com/m?continue=https://news.google.com/rss/articles/CBMijQFodHRwczovL3d3dy5idXNpbmVzc3RvZGF5LmluL21hZ2F6aW5lL2NvcnBvcmF0ZS9zdG9yeS9ib2xseXdvb2RzLXNtYWxsLWJ1ZGdldC1maWxtcy1hcmUtaW4tY3Jpc2lzLW1vZGUtaGVyZXMtd2hhdHMtZ29pbmctb24tMzYxMTE4LTIwMjMtMDEtMTnSAZEBaHR0cHM6Ly93d3cuYnVzaW5lc3N0b2RheS5pbi9hbXAvbWFnYXppbmUvY29ycG9yYXRlL3N0b3J5L2JvbGx5d29vZHMtc21hbGwtYnVkZ2V0LWZpbG1zLWFyZS1pbi1jcmlzaXMtbW9kZS1oZXJlcy13aGF0cy1nb2luZy1vbi0zNjExMTgtMjAyMy0wMS0xOQ?oc%3D5&gl=DE&m=0&pc=n&hl=en-US&src=1

Accessing the above URL, opens a Google Consent form to accept or reject cookies. The get_news() function should return a URL that allows to access the news article directly without Google Consent.

[mirandacross]

I'm also having this issue! I think it may have to do with EU GDPR stuff. Tried getting rid of the consent substring and it didn't work. Any help appreciated!

[ranahaani]

@mirandacross @sohaibrahman64 sorry for late response, you can get original link using request library

import request

requests.head(get_news()['url']).headers['location']

[dpujol04]

Hello all!
For me, your solution didn't work. So, I ended up implementing this one:
orig_url = requests.get(get_news()['url']).url

[murnanedaniel]

Hello all! For me, your solution didn't work. So, I ended up implementing this one: orig_url = requests.get(get_news()['url']).url

This solution works, but is much slower than than getting just the head. Unfortunately getting just the headers doesn't work, as it returns the Google RSS feed URL.