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Verifies if occurrences of elements are unique
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CharlesCreativeContent authored May 12, 2020
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/*
Given an array of integers arr, write a function that returns true if and only if the number of occurrences of each value in the array is unique.
Example 1:
Input: arr = [1,2,2,1,1,3]
Output: true
Explanation: The value 1 has 3 occurrences, 2 has 2 and 3 has 1. No two values have the same number of occurrences.
Example 2:
Input: arr = [1,2]
Output: false
Example 3:
Input: arr = [-3,0,1,-3,1,1,1,-3,10,0]
Output: true
Constraints:
1 <= arr.length <= 1000
-1000 <= arr[i] <= 1000
*/

//Answer//
/**
* @param {number[]} arr
* @return {boolean}
*/
var uniqueOccurrences = function(arr) {
let A = []
let B = [...new Set (arr)]
for (let i = 0; i <B.length ; i++) {
A.push(arr.filter(x=>x===B[i]).length)
}
console.log(typeof Array.from([...new Set(A)]))
return A.length===[...new Set(A)].length
};

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