Skip to content

Commit

Permalink
Finds max pair of multiples
Browse files Browse the repository at this point in the history
  • Loading branch information
CharlesCreativeContent authored Jun 11, 2020
1 parent ff96741 commit e1cf146
Showing 1 changed file with 35 additions and 0 deletions.
35 changes: 35 additions & 0 deletions maximumMultiples.js
Original file line number Diff line number Diff line change
@@ -0,0 +1,35 @@
/*
Given the array of integers nums, you will choose two different indices i and j of that array. Return the maximum value of (nums[i]-1)*(nums[j]-1).
Example 1:
Input: nums = [3,4,5,2]
Output: 12
Explanation: If you choose the indices i=1 and j=2 (indexed from 0), you will get the maximum value, that is, (nums[1]-1)*(nums[2]-1) = (4-1)*(5-1) = 3*4 = 12.
Example 2:
Input: nums = [1,5,4,5]
Output: 16
Explanation: Choosing the indices i=1 and j=3 (indexed from 0), you will get the maximum value of (5-1)*(5-1) = 16.
Example 3:
Input: nums = [3,7]
Output: 12
Constraints:
2 <= nums.length <= 500
1 <= nums[i] <= 10^3
*/

//Answer//
/**
* @param {number[]} nums
* @return {number}
*/
var maxProduct = function(nums) {
let Sort = nums.sort((a,b)=>b-a)
return (Sort[0]-1)*(Sort[1]-1)
};

0 comments on commit e1cf146

Please sign in to comment.