An implementation of the groupBy
Haskell function, providing tools for efficiently iterating over slice
and str
by groups defined by a function that specifies if two elements are in the same group.
The Itertools::group_by
method use a key to compare elements, this library works like, say, slice::sort_by
, it uses a comparison function. It works on every Iterator
type, slice-group-by
work only with slice
and str
, which is the power of this library, it is fast thanks to data locality.
Also slice-group-by
support multiple search algorithms (i.e. linear, binary and exponential search) and can return groups starting from the end.
You will only need to define a function that returns true
if two elements are in the same group.
The LinearGroupBy
iterator will always gives contiguous elements to the predicate function.
use slice_group_by::GroupBy;
let slice = &[1, 1, 1, 3, 3, 2, 2, 2];
let mut iter = slice.linear_group_by(|a, b| a == b);
assert_eq!(iter.next(), Some(&[1, 1, 1][..]));
assert_eq!(iter.next(), Some(&[3, 3][..]));
assert_eq!(iter.next(), Some(&[2, 2, 2][..]));
assert_eq!(iter.next(), None);
You will only need to define a function that returns true
if two char
are in the same group.
The LinearStrGroupBy
iterator will always gives contiguous char
to the predicate function.
use slice_group_by::StrGroupBy;
let string = "aaaabbbbb饰饰cccc";
let mut iter = string.linear_group_by(|a, b| a == b);
assert_eq!(iter.next(), Some("aaaa"));
assert_eq!(iter.next(), Some("bbbbb"));
assert_eq!(iter.next(), Some("饰饰"));
assert_eq!(iter.next(), Some("cccc"));
assert_eq!(iter.next(), None);
It is also possible to get mutable non overlapping groups of a slice.
The BinaryGroupBy/Mut
and ExponentialGroupBy/Mut
iterators will not necessarily
gives contiguous elements to the predicate function. The predicate function should implement
an order consistent with the sort order of the slice.
use slice_group_by::GroupByMut;
let slice = &mut [1, 1, 1, 2, 2, 2, 3, 3];
let mut iter = slice.binary_group_by_mut(|a, b| a == b);
assert_eq!(iter.next(), Some(&mut [1, 1, 1][..]));
assert_eq!(iter.next(), Some(&mut [2, 2, 2][..]));
assert_eq!(iter.next(), Some(&mut [3, 3][..]));
assert_eq!(iter.next(), None);
It is also possible to get mutable non overlapping groups of a slice even starting from end of it.
use slice_group_by::GroupByMut;
let slice = &mut [1, 1, 1, 2, 2, 2, 3, 3];
let mut iter = slice.exponential_group_by_mut(|a, b| a == b).rev();
assert_eq!(iter.next(), Some(&mut [3, 3][..]));
assert_eq!(iter.next(), Some(&mut [2, 2, 2][..]));
assert_eq!(iter.next(), Some(&mut [1, 1, 1][..]));
assert_eq!(iter.next(), None);