Skip to content
New issue

Have a question about this project? Sign up for a free GitHub account to open an issue and contact its maintainers and the community.

By clicking “Sign up for GitHub”, you agree to our terms of service and privacy statement. We’ll occasionally send you account related emails.

Already on GitHub? Sign in to your account

End of Rsa ecc sub branch #11

Merged
merged 2 commits into from
Jan 29, 2024
Merged
Show file tree
Hide file tree
Changes from all commits
Commits
File filter

Filter by extension

Filter by extension


Conversations
Failed to load comments.
Loading
Jump to
Jump to file
Failed to load files.
Loading
Diff view
Diff view
172 changes: 101 additions & 71 deletions Python/Classic Encryption Methods .ipynb
Original file line number Diff line number Diff line change
Expand Up @@ -548,7 +548,7 @@
" if math.sqrt(n + b**2) == math.isqrt(n + b**2) : \n",
" possible_vals.append( ( int( b + math.sqrt(n + b**2) ), int(math.sqrt(n + b**2)-b)))\n",
" \n",
" return (possible_vals)"
" return (possible_vals)\n"
]
},
{
Expand Down Expand Up @@ -586,7 +586,7 @@
},
{
"cell_type": "code",
"execution_count": 64,
"execution_count": 65,
"metadata": {},
"outputs": [
{
Expand All @@ -595,7 +595,7 @@
"[(9671881, 2828971)]"
]
},
"execution_count": 64,
"execution_count": 65,
"metadata": {},
"output_type": "execute_result"
}
Expand All @@ -604,6 +604,104 @@
"fermat_method_simple(p*q)"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"Now we will use this Fermat's factorisation algorithm again, but this time check from the middle, we are guessing that p and q are close together. "
]
},
{
"cell_type": "code",
"execution_count": 90,
"metadata": {},
"outputs": [],
"source": [
"def fermat_method_close(n):\n",
" \n",
" possible_vals = []\n",
" \n",
" for b in range(int(math.sqrt(n)), 0, -1):\n",
" if math.sqrt(n + b**2) == math.isqrt(n + b**2) : \n",
" possible_vals.append( ( int( b + math.sqrt(n + b**2) ), int(math.sqrt(n + b**2)-b)))\n",
" \n",
" return (possible_vals)"
]
},
{
"cell_type": "code",
"execution_count": null,
"metadata": {},
"outputs": [],
"source": [
"# Now let's compare \n",
"\n",
"start = time.time()\n",
"\n",
"p, q = 2828971, 9671881\n",
"\n",
"\n",
"if (p,q) in fermat_method_simple(p*q) or (q,p) in fermat_method_simple(p*q) :\n",
" print ('Correct')\n",
"\n",
"end = time.time()\n",
"\n",
"print(\"The time of execution of the simple loop is :\",\n",
" (end-start) * 10**3, \"ms\")\n",
"\n",
"start = time.time()\n",
"\n",
"if (p,q) in fermat_method_simple(p*q) or (q,p) in fermat_method_close(p*q) :\n",
" print ('Correct')\n",
"\n",
"end = time.time()\n",
"\n",
"print(\"The time of execution of the close version is :\",\n",
" (end-start) * 10**3, \"ms\")"
]
},
{
"cell_type": "code",
"execution_count": null,
"metadata": {},
"outputs": [],
"source": [
"import sympy\n",
"# Lets get a close to adjacent prime to 350185187058915769990977340231\n",
"sympy.nextprime(sympy.nextprime(sympy.nextprime(sympy.nextprime(350185187058915769990977340231))))"
]
},
{
"cell_type": "code",
"execution_count": null,
"metadata": {},
"outputs": [],
"source": [
"# Lets test it on a massive prime factorisation that would take >1h on the first function\n",
"\n",
"p, q = 350185187058915769990977340231, 350185187058915769990977340643\n",
"\n",
"start = time.time()\n",
"\n",
"if (p,q) in fermat_method_close(p*q) or (q,p) in fermat_method_close(p*q) :\n",
" print ('Correct')\n",
"\n",
"end = time.time()\n",
"\n",
"print(\"The time of execution of the close version is :\",\n",
" (end-start) * 10**3, \"ms\")"
]
},
{
"cell_type": "code",
"execution_count": null,
"metadata": {},
"outputs": [],
"source": [
"n= p*q\n",
"fermat_method_close(p*q)\n"
]
},
{
"cell_type": "markdown",
"metadata": {},
Expand Down Expand Up @@ -653,74 +751,6 @@
"Examples include SHA-1, SHA-256, SHA-384, and SHA-512."
]
},
{
"cell_type": "code",
"execution_count": null,
"metadata": {},
"outputs": [],
"source": []
},
{
"cell_type": "code",
"execution_count": null,
"metadata": {},
"outputs": [],
"source": []
},
{
"cell_type": "code",
"execution_count": 2,
"metadata": {},
"outputs": [],
"source": [
"def say_hello():\n",
" print(\"Hello\")\n",
" print(\"Raphael\")"
]
},
{
"cell_type": "code",
"execution_count": 3,
"metadata": {},
"outputs": [
{
"name": "stdout",
"output_type": "stream",
"text": [
"Hello\n",
"Raphael\n"
]
}
],
"source": [
"say_hello()"
]
},
{
"cell_type": "code",
"execution_count": 8,
"metadata": {},
"outputs": [
{
"name": "stdout",
"output_type": "stream",
"text": [
"0\n",
"1\n",
"2\n",
"3\n",
"4\n"
]
}
],
"source": [
"a = 5 \n",
"i = 0\n",
"while i<a:\n",
" print(i)\n",
" i = i + 1 "
]
},
{
"cell_type": "code",
"execution_count": null,
Expand Down
14 changes: 7 additions & 7 deletions Rust/encryptions/Cargo.lock

Some generated files are not rendered by default. Learn more about how customized files appear on GitHub.

2 changes: 1 addition & 1 deletion Rust/encryptions/Cargo.toml
Original file line number Diff line number Diff line change
@@ -1,5 +1,5 @@
[package]
name = "Cryptography"
name = "encryptions"
version = "0.1.0"
edition = "2021"

Expand Down
23 changes: 23 additions & 0 deletions Rust/encryptions/src/main.rs
Original file line number Diff line number Diff line change
Expand Up @@ -22,6 +22,17 @@ impl UserWeak {
UserWeak { name, prime_p, prime_q, e, n, eulers_totient, d, inbox: Vec::new(), }
}

fn encrypt_message(&self, message: &BigInt) -> BigInt {
message.modpow(&self.e, &self.n)
}

fn decrypt_message(&self, cipher: &BigInt) -> BigInt {
cipher.modpow(&self.d, &self.n)
}

fn send_message(&self, recipient: UserWeak, message: &i32)-> () {

}


}
Expand All @@ -48,6 +59,8 @@ fn mod_inv(a: &BigInt, m: &BigInt) ->Option<BigInt>{





fn main() {
// Example prime numbers and exponent for RSA. In a real application, choose large primes.
//John = User_weak("John", 27647, 60041, 1579)
Expand All @@ -57,7 +70,17 @@ fn main() {

let user = UserWeak::new("John Doe".to_string(), prime_p, prime_q, e);


// Let us check is a user can be created
println!("User created: {:?}", user);

// Encrypt and Decrypt a message (here a BigInt)
let mess = BigInt::from(123u32);
let cipher = user.encrypt_message(&mess);
println!("{}", cipher);
let mess2 = user.decrypt_message(&cipher);
println!("{}", mess2);
}